Montag, 29. August 2011

EE4206/EE5806 : digital image processing -- tutorial 1 answer

http://docstore.mik.ua/orelly/

http://www.eespeech.cityu.edu.hk/~ebook/ee5806/

username : student
password: image

click image processing -> click Notes download (PDF format )

Tutorial 1

Assume that a video system has

- Each frame size 512 by 512;
- 30 frames/ second;
- 8 bits for each color component.

(1) What is the minimum data rate needed to transmit the video if the data are uncompressed?

ans: 512* 512* 30* 3 bytes = 23592960 bytes = 23 MB ( 3 bytes = 24 bits ( 8 bits for each color component) )


(2) What compression ratio is needed to transmit the data through a modem with the speed of 56K bit/s?

ans : convert it to bits : 23592960 * 8 / (56 * 1024)

(3) Suppose that we can down-sample the image to reduce the amount of data. For a compression ratio of 100, what is the maximum image size the above modem can handle?

ans : let the unknown be x : (convert it to bits )

(x^2 )* 30* 3* 8/ 100 = 56* 1024
x^2 = 7964
x = 79





Keine Kommentare: